Matematika Q.[tex] \\ \\ \\ [/tex]f(x) = 4x² + 4⁰ + 9⁰ + 2f(2) = ..[tex] \\ \\ \\ [/tex]130 + 20 = ..[tex] \\ \\ \\ \\ [/tex]5! = ..[tex] \\ \\ \\ \\ [/tex]2! + 2 = ..[tex] \\ \\ \\ \\ [/tex]​

gaetanobodeulv – April 02, 2023

Q.
[tex] \\ \\ \\ [/tex]
f(x) = 4x² + 4⁰ + 9⁰ + 2
f(2) = ..

[tex] \\ \\ \\ [/tex]
130 + 20 = ..

[tex] \\ \\ \\ \\ [/tex]
5! = ..

[tex] \\ \\ \\ \\ [/tex]
2! + 2 = ..

[tex] \\ \\ \\ \\ [/tex]
​

Jawaban:

[[ No 1 ]]

f(x) = 4x² + 4⁰ + 9⁰ + 2

f(2) = 4(2)² + 4⁰ + 9⁰ + 2

f(2) = 4(2×2) + 1 + 1 + 2

f(2) = (4×4) + 1 + 1 + 2

f(2) = 16 + 1 + 1 + 2

f(2) = 17 + 1 + 2

f(2) = 18 + 2

f(2) = 20✓

-------------

[[ No 2 ]]

= 130 + 20

= 150✓

-------------

[[ No 3 ]]

5!

= 5 × 4 × 3 × 2 × 1

= 20 × 3 × 2 × 1

= 60 × 2 × 1

= 120 × 1

= 120✓

--------------

[[ No 4 ]]

2! + 2

= (2×1) + 2

= 2 + 2

= 4✓

--------------

..

Nomor 1

f(x) = 4x² + 4⁰ + 9⁰ + 2

f(2) = 4(2²) + 1 + 1 + 2

= 4(4) + 4

= 16 + 4

= 20

Nomor 2

130 + 20

= 150

Nomor 3

5!

= 5 × 4 × 3 × 2 × 1

= 20 × 6 × 1

= 120

Nomor 4

2! + 2

= (2 × 1) + 2

= 2 + 2

= 4

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